(x-1)^2+(x+3)^2=2(x-2)+x+39

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Solution for (x-1)^2+(x+3)^2=2(x-2)+x+39 equation: 



(x-1)^2+(x+3)^2=2(x-2)+x+39

We move all terms to the left:

(x-1)^2+(x+3)^2-(2(x-2)+x+39)=0



We calculate terms in parentheses: -(2(x-2)+x+39), so:

2(x-2)+x+39

We add all the numbers together, and all the variables

x+2(x-2)+39

We multiply parentheses

x+2x-4+39

We add all the numbers together, and all the variables

3x+35

Back to the equation:

-(3x+35)



We get rid of parentheses

(x-1)^2+(x+3)^2-3x-35=0

We add all the numbers together, and all the variables

-3x+(x-1)^2+(x+3)^2-35=0

We move all terms containing x to the left, all other terms to the right

-3x+(x-1)^2+(x+3)^2=35

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